document.write( "Question 553658: A car dealer sold two cars. On the first car he made a 10% profit and on the second car he lost 10%. He sold the cars for $9999 each. What was the overall dollar amount of profit or loss on the two transactions, or did the dealer break even? \n" ); document.write( "
Algebra.Com's Answer #360981 by Maths68(1474)\"\" \"About 
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Total value of two cars = 9999+9999 = 19998
\n" ); document.write( "First Car was sold on 10% profit = 9999*10/100=99990/100=999.90
\n" ); document.write( "Second Car was sold on 10% loss = 9999*10/100=99990/100=999.90\r
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\n" ); document.write( "\n" ); document.write( "Total amount of two cars after sale = (value of first car + profit)+ (Value of Second car - loss)
\n" ); document.write( "Total amount of two cars after sale = (9999+999.90)+(9999-999.90)
\n" ); document.write( "Total amount of two cars after sale = 10998.90+8999.10
\n" ); document.write( "Total amount of two cars after sale = 19998\r
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\n" ); document.write( "\n" ); document.write( "Total value of two cars before sale= Total value of two cars after sale
\n" ); document.write( "19998=19998\r
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\n" ); document.write( "\n" ); document.write( "Dealer broke even.\r
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