document.write( "Question 553609: one solution is 20% acid and another is 70% acid. How many liters of each solution should you use to make 4 liters of a 55% solution \n" ); document.write( "
Algebra.Com's Answer #360961 by mananth(16946)\"\" \"About 
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percent ----------------quantity
\n" ); document.write( "Acid type I 20 ----------------x liters
\n" ); document.write( "Acid type II 70 ----------------4-x liters
\n" ); document.write( "Mixture 55.00% ---------------- 4
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\n" ); document.write( "20x+70(4-x)=55*4
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\n" ); document.write( "20x+280-70x=220
\n" ); document.write( "20x-70x=220-280
\n" ); document.write( "-50x=-60
\n" ); document.write( "/-50
\n" ); document.write( "x=1.2 liters 20.00% Acid type I
\n" ); document.write( "2.8 liters 70.00% Acid type II
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