document.write( "Question 553468: what are the equations for both asymptotes of the following hyperbola (y^2)/(16)-(x^2)/(9)=1 \n" ); document.write( "
Algebra.Com's Answer #360919 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! what are the equations for both asymptotes of the following hyperbola (y^2)/(16)-(x^2)/(9)=1 \n" ); document.write( "*** \n" ); document.write( "(y^2)/(16)-(x^2)/(9)=1 \n" ); document.write( "This is an equation of a hyperbola with vertical transverse axis. \n" ); document.write( "Its standard form: (x-h)^2/a^2-(y-k)^2/b^2=1, with (h,k) being the (x,y) coordinates of the center. \n" ); document.write( "For given equation: \n" ); document.write( "Center: (0,0) \n" ); document.write( "a^2=16 \n" ); document.write( "a=√16=4 \n" ); document.write( "b^2=9 \n" ); document.write( "b=√9=3 \n" ); document.write( "Asymptotes for hyperbolas are straight lines which go thru the center and are of the standard form: y=mx+b, m=slope, b=y-intercept. \n" ); document.write( "For given equation: \n" ); document.write( "Slopes of asymptotes: ±a/b=±4/3 \n" ); document.write( "y-intercept=0 \n" ); document.write( "Equation of asymptotes: \n" ); document.write( "y=-4x/3+0=-4x/3 \n" ); document.write( "and \n" ); document.write( "y=4x/3+0=4x/3 \n" ); document.write( " |