document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=553500>Question 553500</A>: <I><SPAN STYLE=\"word-break: break-all;\"> x to the 6th - 9y to the 2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #360871 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=360871\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^6 - 9y^2 factors out to be (x^3 - 3y)(x^3 + 3y).\r<BR>\n" );
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document.write( "If you multiply (x^3 - 3y) by (x^3 + 3y), it will take you back to the given problem.  This is how we know when the answer is correct in terms of factoring.  \r<BR>\n" );
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document.write( "Factoring is the opposite of multiplication.\r<BR>\n" );
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document.write( "Understand?<BR>\n" );
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