document.write( "Question 553499: Mrs. Hill is 33 years older than her son. In 4 years she will be four times as old as her son. How old is each?\r
\n" );
document.write( "\n" );
document.write( "I am not sure how to define all this to actually get the answer. what i have so far is x= son. so the equation I have so far is 33+x; 4+x+4x \n" );
document.write( "
Algebra.Com's Answer #360870 by nyc_function(2741)![]() ![]() You can put this solution on YOUR website! Let her son be s years old. She is s + 33 years old.\r \n" ); document.write( "\n" ); document.write( "In four years time this becomes s + 4 and s + 37.\r \n" ); document.write( "\n" ); document.write( "so, 4(s + 4) = s + 37\r \n" ); document.write( "\n" ); document.write( "=> 4s + 16 = s + 37\r \n" ); document.write( "\n" ); document.write( "=> 3s = 21\r \n" ); document.write( "\n" ); document.write( "so, s = 7\r \n" ); document.write( "\n" ); document.write( "i.e. their ages are 7 and 40.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |