document.write( "Question 553434: solve the system of equations using the substitution method
\n" ); document.write( "x+z=8
\n" ); document.write( "y-z=5
\n" ); document.write( "x-y=9
\n" ); document.write( "

Algebra.Com's Answer #360847 by Theo(13342)\"\" \"About 
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your 3 equations are:
\n" ); document.write( "x+z=8 (first equation)
\n" ); document.write( "y-z=5 (second equation)
\n" ); document.write( "x-y=9 (third equation)
\n" ); document.write( "from the first equation you get x = 8-z
\n" ); document.write( "from the second equation you get y = z+5
\n" ); document.write( "substitute for x and y in the third equation to get:
\n" ); document.write( "8-z - (z+5) = 9
\n" ); document.write( "simplify to get:
\n" ); document.write( "8-z-z-5 = 9
\n" ); document.write( "combine like terms to get:
\n" ); document.write( "3-2z = 9
\n" ); document.write( "subtract 3 from both sides of the equation to get:
\n" ); document.write( "-2z = 6
\n" ); document.write( "divide both sides of the equation by -2 to get:
\n" ); document.write( "z = -3
\n" ); document.write( "substitute for z in first equation to get:
\n" ); document.write( "x = 11
\n" ); document.write( "substitute for z in the second equation to get:
\n" ); document.write( "y = 2
\n" ); document.write( "your solution set is:
\n" ); document.write( "x = 11
\n" ); document.write( "y = 2
\n" ); document.write( "z = -3
\n" ); document.write( "substitute in all 3 original equations to get:
\n" ); document.write( "x+z=8 becomes 11-3 = 8 which becomes 8 = 8
\n" ); document.write( "y-z=5 becomes 2+3 = 5 which becomes 5 = 5
\n" ); document.write( "x-y=9 becomes 11-2 = 9 which becomes 9 = 9
\n" ); document.write( "solutions are confirmed as good.
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