document.write( "Question 552780: the focus and directrix of a parabola are given. the focua is (3,5) and the directrix is y=1 . write the equation of the parabola and then draw the graph. \n" ); document.write( "

Algebra.Com's Answer #360830 by lwsshak3(11628) $\"\"$ $\"About$

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the focus and directrix of a parabola are given. the focua is (3,5) and the directrix is y=1 . write the equation of the parabola and then draw the graph.
\n" ); document.write( "Standard form of equation for parabola: (x-h)^2=4p(y-k), (h,k) being the (x,y) coordinates of the vertex.
\n" ); document.write( "For given equation:
\n" ); document.write( "Parabola opens upwards
\n" ); document.write( "axis of symmetry: x=3
\n" ); document.write( "p=half the distance between directrix and focus on the axis of symmetry=4/2=2
\n" ); document.write( "y-coordinate of vertex=3
\n" ); document.write( "vertex: (3,3)
\n" ); document.write( "Equation of parabola:
\n" ); document.write( "(x-3)^2=8(y-3)
\n" ); document.write( "or
\n" ); document.write( "y=(1/8)(x-3)^2+3
\n" ); document.write( " $\"+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C%28x-3%29%5E2%2F8%2B3%29+\"$ \n" ); document.write( "

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