document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=53850>Question 53850</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Stefan has 42 coins in his collection. The coins consist of nickles, dimes, and quarters. He has twice as many quarters as dimes. Although the collection has been appraised at $1200, the coins' face value is $6.60. How many of each type of coin does he have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #36083 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=36083\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 42=N+D+2D OR 42=N+3D OR N=42-3D & 5N+10D+25*2D=660 OR 5N+60D=660 THEN SUBSTITUTING 42-3D FOR N WE GET 5(42-3D)+60D=660 OR 210-15D+60D=660 OR<BR>\n" );
document.write( "210+45D=660 OR 45D=660-210 OR 45D=450 OR D=450/45 OR D=10 THEREFORE WE HAVE \r<BR>\n" );
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document.write( "42=N+3*10 OR N=42-30 OR N=12 \r<BR>\n" );
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document.write( "PROOF 660=5*12+10*10+20*25 OR 660=60+100+500 OR 660=660<BR>\n" );
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