document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=53807>Question 53807</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A line that is perpendicular to 3x-9y=13 through (2,-4)this is what I did:<BR>\n" );
document.write( "-9y=13-3x<BR>\n" );
document.write( "divided all by -9 to get<BR>\n" );
document.write( "y=-13/9-1/3x<BR>\n" );
document.write( "slope =-1/3<BR>\n" );
document.write( "y-(-4)=-1/3(x-2)<BR>\n" );
document.write( "y+4=-1/3x+2/3<BR>\n" );
document.write( "y=-1/3x+2/3-4<BR>\n" );
document.write( "y=-1/3x-3 1/3\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #36080 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=36080\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> SORRY FOR THE OVERSIGHT. I JUST HAD LASER SURGERY THIS MORNING & MY LEFT EYE IS STILL BLURRED. HOWEVER I SHOULD HAVE RECHECKED MY MATH. \r<BR>\n" );
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document.write( "3X-9Y=13 OR -9Y=3X-13 OR -Y=3/9X-13/9 OR -Y=1/3X-13/9 or Y=-1/3X+13/9 SO THE PERPENDICULAR LINE HAS A SLOPE OF 3 THE NEGATIVE RECIPRICAL OF THE SLOPE OF <BR>\n" );
document.write( "-1/3<BR>\n" );
document.write( "SO THE EQUATION OF THE LINE WITH A SLOPE OF 3 THROUGH (2,-4) IS \r<BR>\n" );
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document.write( "Y=3X+b or -4=3*2+b or -4=6+b or b=-10 thus the equatiion is y=3x-10 </SPAN>\n" );
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