document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=553311>Question 553311</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A plane left an airport and flew with the wind for 4 hours, covering 2000 miles. It then returned over the same route to the airport against the same wind in 5 hours. Find the rate of the plane in still air and the speed of the wind. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #360787 by </B><A HREF=/tutors/aboutme.mpl?userid=prateekagrawal><B>prateekagrawal(56)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=prateekagrawal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=360787\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> in both the cases distance is same.<BR>\n" );
document.write( "for case 1 speed is 2000/4 = 500mph<BR>\n" );
document.write( "and for case 2 speed is 2000/5 = 400mph.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "average of sum of  these will provide speed of plane.<BR>\n" );
document.write( "so, speed of plane = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28500%2B400%29%2F2+=+900%2F2+=+450mph ALIGN=MIDDLE  ALT=\"%28500%2B400%29%2F2+=+900%2F2+=+450mph\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( ".<BR>\n" );
document.write( "and speed of wind= 500 - 450 = 50mph. </SPAN>\n" );
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