document.write( "Question 553192: A manufacturer of a consumer electronics product expects 2% of units to fail during the warranty period. A sample of 500 independent units is tracked for warranty performance. \r
\n" ); document.write( "\n" ); document.write( "(a) What is the probability that none fails during the warranty period?
\n" ); document.write( "(b) What is the expected number of failures during the warranty period?
\n" ); document.write( "(c) What is the probability that more than two units fail during the warranty period?
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Algebra.Com's Answer #360733 by stanbon(75887)\"\" \"About 
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A manufacturer of a consumer electronics product expects 2% of units to fail during the warranty period. A sample of 500 independent units is tracked for warranty performance.
\n" ); document.write( "Binomial Problem with n = 500 and p(fail) = 0.02 and P(good) = 0.98
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\n" ); document.write( "(a) What is the probability that none fails during the warranty period?
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\n" ); document.write( "P(x = 500) = 0.98^500 = 0.000041024
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\n" ); document.write( "(b) What is the expected number of failures during the warranty period?
\n" ); document.write( "Expected number = mean = np = 500*0.02 = 10
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\n" ); document.write( "(c) What is the probability that more than two units fail during the warranty period?
\n" ); document.write( "P(x >= 3) = 1 - P(0<= x <=2) = 1 - binomcdf(500,0.02,2) = 0.9974
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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