document.write( "Question 553110: Solve:\r
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document.write( "Include a sketch to support answer.\r
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document.write( "I isolated x to get and
but I don't understand how x is greater than or equal to
and less than or equal to
. I also don't know how to do the sketch. \n" );
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Algebra.Com's Answer #360691 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Solve: \n" ); document.write( "2 /(x^2-1) >= -3 \n" ); document.write( "------ \n" ); document.write( "x cannot be -1 ; x cannot be +1 \n" ); document.write( "------ \n" ); document.write( "Draw a number line and plot x = -1 and x = 1 \n" ); document.write( "----\r \n" ); document.write( "\n" ); document.write( "----- \n" ); document.write( "Solve the Equality: \n" ); document.write( "2 = -3(x^2-1) \n" ); document.write( "2 = -3x^2+3 \n" ); document.write( "3x^2 = 1 \n" ); document.write( "x^2 = 1/3 \n" ); document.write( "x = +-sqrt(3/3) \n" ); document.write( "------ \n" ); document.write( "Plot those values on the number line. \n" ); document.write( "-------------- \n" ); document.write( "You now have values at -1, -1/sqrt(3), 1/sqrt(3), +1 \n" ); document.write( "Find the solution set by testing a value in each \n" ); document.write( "of the resulting 5 intervals: \n" ); document.write( "---- \n" ); document.write( "2 /(x^2-1) > -3 \n" ); document.write( "Test x = -10:: 2/(99)> -3 ; true ; solutions in (-oo,-1) \n" ); document.write( "Test x = -3/4 ; 2/(-7/16) > -3 ; false \n" ); document.write( "Test x = 0 ; 2/-1 > -3 ; true ; solutions in [-sqrt(1/3),sqrt(1/3] \n" ); document.write( "Test x = +3/4 ; 2/(-7/15) > false \n" ); document.write( "Test x = 10 ; 2/99 > -3 ; true ; solutions in (1,+oo) \n" ); document.write( "========================================================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "========== \n" ); document.write( " |