document.write( "Question 552790: the focus of a parabola is (4, -3) and the directrix is y=6\r
\n" ); document.write( "\n" ); document.write( "write the equation of the parabola and then draw the graph.
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Algebra.Com's Answer #360578 by lwsshak3(11628)\"\" \"About 
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the focus of a parabola is (4, -3) and the directrix is y=6
\n" ); document.write( "write the equation of the parabola and then draw the graph
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\n" ); document.write( "Equation is that of a parabola which opens downward. Its standard form: (x-h)^2=-4p(y-k), with (h,k) being the (x,y) coordinates of the vertex.
\n" ); document.write( "For given equation:
\n" ); document.write( "axis of symmetry: x=4
\n" ); document.write( "p=half the distance between the directrix and y-coordinate of the focus on the axis of symmetry.
\n" ); document.write( "p=(6+3)/2=9/2=4.5
\n" ); document.write( "vertex: (4, 3/2)
\n" ); document.write( "Equation of parabola:
\n" ); document.write( "y=(x-4)^2/-18+3/2
\n" ); document.write( "see graph below
\n" ); document.write( "\"+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C%28x-4%29%5E2%2F-18%2B3%2F2%29+\"
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