document.write( "Question 552799: Graph the equation. Identify the vertices, co vertices, and foci of the ellipse.
\n" ); document.write( "{[(x^2)/16]+[(y^2)/4]}=1
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Algebra.Com's Answer #360575 by lwsshak3(11628)\"\" \"About 
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Graph the equation. Identify the vertices, co vertices, and foci of the ellipse.
\n" ); document.write( "{[(x^2)/16]+[(y^2)/4]}=1
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\n" ); document.write( "(x^2)/16+(y^2)/4=1
\n" ); document.write( "This is an equation for an ellipse with horizontal major axis. Its standard form:
\n" ); document.write( "y=(x-h)^2/a^2+(y-k)^2/b^2, a>b, with (h,k) being the (x,y) coordinates of the center.
\n" ); document.write( "For given equation:
\n" ); document.write( "Center: (0, 0)
\n" ); document.write( "a^2=16
\n" ); document.write( "a=√16=4
\n" ); document.write( "b^2=4
\n" ); document.write( "b=2
\n" ); document.write( "c^2=a^2-b^2=16-4=12
\n" ); document.write( "c=(x^2)/16]+[(y^2)/4]}=√12≈3.46
\n" ); document.write( "..
\n" ); document.write( "vertices: (0±a,0)=(0±4,0)=(-4,0) and (4,0)
\n" ); document.write( "Co-vertices: (0,0±b)=(0,0±2)=(0,-2) and (0,2)
\n" ); document.write( "Foci:(0±c,0)=(0±√12,0)=(-3.46,0) and (3.46,0)
\n" ); document.write( "see graph below:
\n" ); document.write( "..
\n" ); document.write( "y=±(4-x^2/4)^.5
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