document.write( "Question 552895: The sum of the digits of a two-digit number is 15. If the digits are reversed, the number is increased by 9. What is the original number? \n" ); document.write( "

Algebra.Com's Answer #360559 by mananth(16946) $\"\"$ $\"About$

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x+y= 15 .............1
\n" ); document.write( "10y+x=10x+y+9
\n" ); document.write( "9y=9+9x ---------2
\n" ); document.write( "/9 =
\n" ); document.write( "y=1+x
\n" ); document.write( "Substitute y in (1)
\n" ); document.write( "x+(1+x) =15
\n" ); document.write( "x+1+x = 15
\n" ); document.write( "x+x=15-1
\n" ); document.write( "2x = 14
\n" ); document.write( "/ 2
\n" ); document.write( "x= 7
\n" ); document.write( "Plug the value of x in (1)
\n" ); document.write( "x+y=15
\n" ); document.write( "1*7+ y=15
\n" ); document.write( "7+y=15
\n" ); document.write( "y=8
\n" ); document.write( "/ 1
\n" ); document.write( "y= 8
\n" ); document.write( "The number is 78
\n" ); document.write( "m.ananth@hotmail.ca
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