document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=552835>Question 552835</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the system using substitution.\r<BR>\n" );
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document.write( "y = 3x - 6<BR>\n" );
document.write( "-3x + y = -6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #360537 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=360537\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve the system using substitution.\r<BR>\n" );
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document.write( "y = 3x - 6<BR>\n" );
document.write( "-3x + y = -6<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "Sub for y in the 2nd eqn:<BR>\n" );
document.write( "-3x + (3x-6) = -6<BR>\n" );
document.write( "-6 = -6<BR>\n" );
document.write( "--------<BR>\n" );
document.write( "--> Dependent.  The 2 eqns are the same, no unique solution.<BR>\n" );
document.write( " </SPAN>\n" );
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