document.write( "Question 552716: A cliff diver throws a pebble that take three seconds to strike the water. About how high is the diver above water? how do i solve with h(t)==4.9t^2+h? \n" ); document.write( "

Algebra.Com's Answer #360502 by Earlsdon(6294) $\"\"$ $\"About$

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The function is:
\n" ); document.write( " $\"h%28t%29+=+-4.9t%5E2%2Bh%5B0%5D\"$ which allows you to calculate the height (in meters) of of an object dropped from an initial height of $\"h%5B0%5D\"$ as a function of time (t in secods).
\n" ); document.write( "When the object (pebble) reaches the ground, h = 0, so substitute this and t = 3 into the equation and solve for the corresponding value of $\"h%5B0%5D\"$ .
\n" ); document.write( " $\"0+=+-4.9%283%29%5E2%2Bh%5B0%5D\"$
\n" ); document.write( " $\"h%5B0%5D+=+44.1\"$ meters. \n" ); document.write( "

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