document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=552667>Question 552667</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A total of $3000 is invested, part at 2% simple interest and part at 4%. If the total<BR>\n" );
document.write( "annual return from the two investments is $100, how much is invested at each<BR>\n" );
document.write( "rate? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #360464 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=360464\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = the amount invested at 2% while the remainder ($3,000-x) is the amount invested at 4%.<BR>\n" );
document.write( "The interest earned on the two amounts can be expressed as:<BR>\n" );
document.write( "0.02x and 0.04(3000-x) and the sum of these earnings is $100.00<BR>\n" );
document.write( "Here's the equation you'll need to solve for x.<BR>\n" );
document.write( "0.02x+0.04(3000-x) = 100 simpify.<BR>\n" );
document.write( "0.02x+120-0.04x = 100 Combine the x-terms.<BR>\n" );
document.write( "-0.02x+120 = 100 Subtract 120 from both sides.<BR>\n" );
document.write( "-0.02x = -20 Finally, divide both sides by -0.02<BR>\n" );
document.write( "x = 1000 and 3000-x = 2000<BR>\n" );
document.write( "$1000 was invested at 2% and $2000 was invested at 4%\r<BR>\n" );
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