document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=552670>Question 552670</A>: <I><SPAN STYLE=\"word-break: break-all;\"> At your lemonade stand you charge .50 for a half cup and .75 for a full cup. At the end of the day, you see 12 cups were used and you made $8.00. How many of each size of drink did you ssll </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #360450 by </B><A HREF=/tutors/aboutme.mpl?userid=fcabanski><B>fcabanski(1391)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fcabanski><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=360450\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call half cups H and full cups F.<P><BR>\n" );
document.write( "12 cups were used so H + F = 12<P><BR>\n" );
document.write( "You sold $8 so .5H + .75F = 8<P><BR>\n" );
document.write( "Solve the first equation in terms of one variable.<BR>\n" );
document.write( "H+F=12 <BR>\n" );
document.write( "F = 12-H | Substitute that into the second equation.<BR>\n" );
document.write( ".5H + .75(12-H) = 8<BR>\n" );
document.write( ".5H + 9 - .75H = 8<BR>\n" );
document.write( "-.25H = -1<BR>\n" );
document.write( "H = 4<P><BR>\n" );
document.write( "H+F = 12<BR>\n" );
document.write( "4+F=12<BR>\n" );
document.write( "F=12-4=8<BR>\n" );
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