document.write( "Question 552188: What is the the exact value of sec 17π/4 using periodic properties? \n" ); document.write( "
Algebra.Com's Answer #360447 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! What is the the exact value of sec 17π/4 using periodic properties? \n" ); document.write( "** \n" ); document.write( "let us work with the more familiar function, the cosine. \n" ); document.write( "17π/4=16π/4+π/4 \n" ); document.write( "16π/4=4π or= two periods \n" ); document.write( "moving an additional π/4 makes cos π/4=√2/2 or sec π/4=√2 \n" ); document.write( "ans: \n" ); document.write( "sec 17π/4= √2 \n" ); document.write( " |