\r\n" );
document.write( "
\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Since the numerator has a higher degree than the denominator, before we can do\r\n" );
document.write( "partial fractions, we must first do the long division to get a rational\r\n" );
document.write( "expression which has a numerator of lower degree than the denominator:\r\n" );
document.write( "\r\n" );
document.write( " x + 0 \r\n" );
document.write( "2x³ + 5x² + 8x + 3)2x4 + 5x³ + 11x² - 15x - 3\r\n" );
document.write( " 2x4 + 5x³ + 8x² + 3x\r\n" );
document.write( " 0x³ + 3x² - 18x - 3\r\n" );
document.write( " 0x³ + 0x² + 0x + 0\r\n" );
document.write( " 3x² - 18x - 3\r\n" );
document.write( "\r\n" );
document.write( "
= x +
\r\n" );
document.write( "\r\n" );
document.write( "We'll break
into partial fractions. Then\r\n" );
document.write( "we'll come back and add the x quotient to it.\r\n" );
document.write( "\r\n" );
document.write( "Now we factor the denominator. We are told that 2x+1 is a factor, so we\r\n" );
document.write( "divide that into the denominator\r\n" );
document.write( "\r\n" );
document.write( " x² + 2x + 3 \r\n" );
document.write( "2x + 1)2x³ + 5x² + 8x + 3\r\n" );
document.write( " 2x³ + x²\r\n" );
document.write( " 4x² + 8x\r\n" );
document.write( " 4x² + 2x\r\n" );
document.write( " 6x + 3\r\n" );
document.write( " 6x + 3 \r\n" );
document.write( "\r\n" );
document.write( "x²+2x+3 does not factor, so we have \r\n" );
document.write( "\r\n" );
document.write( "
=
\r\n" );
document.write( "\r\n" );
document.write( "to break into partial fractions:\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "
=
+
\r\n" );
document.write( "\r\n" );
document.write( "Multiply through by the LCD\r\n" );
document.write( "\r\n" );
document.write( "3x² - 18x - 3 = A(x² + 2x + 3) + (Bx + C)(2x + 1)\r\n" );
document.write( "\r\n" );
document.write( "This must be true for all values of x, so we substitute various values for x:\r\n" );
document.write( "\r\n" );
document.write( "Substituting x=0\r\n" );
document.write( "\r\n" );
document.write( "3(0)² - 18(0) - 3 = A((0)² + 2(0) + 3) + (B(0) + C)(2(0) + 1)\r\n" );
document.write( "\r\n" );
document.write( " -3 = 3A + C \r\n" );
document.write( "\r\n" );
document.write( "Substituting x=1\r\n" );
document.write( "\r\n" );
document.write( "3(1)² - 18(1) - 3 = A((1)² + 2(1) + 3) + (B(1) + C)(2(1) + 1)\r\n" );
document.write( " 3 - 18 - 3 = A(1 + 2 + 3) + (B + C)(2 + 1)\r\n" );
document.write( " -18 = A(6) + (B + C)(3)\r\n" );
document.write( " -18 = 6A + 3B + 3C\r\n" );
document.write( "\r\n" );
document.write( "Substituting x=-1\r\n" );
document.write( "\r\n" );
document.write( "3(-1)² - 18(-1) - 3 = A((-1)² + 2(-1) + 3) + (B(-1) + C)(2(-1) + 1)\r\n" );
document.write( " 3 + 18 - 3 = A(1 - 2 + 3) + (-B + C)(-2 + 1)\r\n" );
document.write( " 18 = A(2) + (-B + C)(-1)\r\n" );
document.write( " 18 = 2A + B - C\r\n" );
document.write( "\r\n" );
document.write( "So we solve the system of three equations:\r\n" );
document.write( "\r\n" );
document.write( "-3 = 3A + C\r\n" );
document.write( "-18 = 6A + 3B + 3C\r\n" );
document.write( "18 = 2A + B - C\r\n" );
document.write( "\r\n" );
document.write( "and get A=3, B=0, C=-12\r\n" );
document.write( "\r\n" );
document.write( "So\r\n" );
document.write( "\r\n" );
document.write( "
=
+
\r\n" );
document.write( " \r\n" );
document.write( "
=
-
\r\n" );
document.write( "\r\n" );
document.write( "Therefore going back to the original problem:\r\n" );
document.write( "\r\n" );
document.write( "
= x +
-
\r\n" );
document.write( "\r\n" );
document.write( "Edwin
\n" );
document.write( "