document.write( "Question 552582: How do you factor the square root of 252x^3y^4? I have a bunch of problems like this, this is just the first one. I have asked several people for help but we are all stumped. I would very much appreciate a simple explanation of how to do this. \n" ); document.write( "

Algebra.Com's Answer #360398 by vleith(2983) $\"\"$ $\"About$

You can put this solution on YOUR website!
You take each factor and do a sqrt on it. Sometimes the factor ae perfect squares, but most times they are not. Many times the factors include something that IS a perfect square. So let's do the problem you noted in a detailed step by step way. Once you see the method, you will be able to skip some of the steps
\n" ); document.write( " $\"sqrt%28252x%5E3y%5E4%29\"$ \r
\n" ); document.write( "\n" ); document.write( "First thing is to know you can break the factors into smaller peices.
\n" ); document.write( " $\"sqrt%28252%29+%2A+sqrt%28x%5E3%29+%2A+sqrt%28y%5E4%29\"$ \r
\n" ); document.write( "\n" ); document.write( "Now factor these smaller pieces with an eye on trying to find factors that are squares. Then do the square root on each of the smaller factors
\n" ); document.write( " $\"sqrt%2836%2A7%29+%2A+sqrt%28x%5E2+%2A+x%29+%2A+sqrt%28y%5E4%29\"$
\n" ); document.write( " $\"sqrt%2836%29+%2A+sqrt%287%29+%2A+sqrt%28x%5E2%29+%2A+sqrt%28x%29+%2A+sqrt%28y%5E4%29\"$
\n" ); document.write( " $\"6+%2A+sqrt%287%29+%2A+x+%2A+sqrt%28x%29+%2A+y%5E2\"$
\n" ); document.write( " $\"6xy%5E2%2Asqrt%287x%29\"$ \n" ); document.write( "

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