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You can put this solution on YOUR website!
problem is:
\n" ); document.write( "tan (cos^-1(7/15))
\n" ); document.write( "first fine cosine^-1(7/15)
\n" ); document.write( "that equals 62.181860723 degrees.
\n" ); document.write( "then find tan (62.181860723)
\n" ); document.write( "that equals 1.895214166
\n" ); document.write( "that's doing it using the calculator.
\n" ); document.write( "now to do it the way i think they want it.
\n" ); document.write( "you have a triangle.
\n" ); document.write( "call it ABC
\n" ); document.write( "assume it's a right triangle.
\n" ); document.write( "AB is the hypotenuse of this right triangle.
\n" ); document.write( "BC is the vertical leg of this right triangle.
\n" ); document.write( "AC is the horizontal leg of this right triangle.
\n" ); document.write( "the length of AC is 7.
\n" ); document.write( "the length of AB is 15
\n" ); document.write( "the length of BC is calculated to be sqrt(176) using the pythagorus theorem of a^2 + b^2 = c^2 where a and b are legs of a right triangle and c is the hypotenuse.
\n" ); document.write( "the angle you are working with is angle x which is the same as angle BAC.
\n" ); document.write( "cosine^-1 (7/15) points to angle x which is the same as angle BAC.
\n" ); document.write( "that's because cosine(x) = adj/hyp = 7/15.
\n" ); document.write( "tan(x) = opp/adj = sqrt(176)/7.
\n" ); document.write( "you have:
\n" ); document.write( "cosine^-1(7/15) = x
\n" ); document.write( "tan(x) = sqrt(176)/7
\n" ); document.write( "since sqrt(176)/7 equals 1.895214166, this method provides the exact same answer as the method i used up top.
\n" ); document.write( "a picture of your triangle is shown below:
\n" ); document.write( "
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