document.write( "Question 552481: at 7:00am, two joggers start from opposite end of an 8 mile course. one jogger is running at a rate of 4mph, and the other is running at a rate og 6mph. at what time will the joggers meet? \n" ); document.write( "

Algebra.Com's Answer #360333 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"+t+\"$ = time in hrs it takes to meet
\n" ); document.write( "Let $\"+d+\"$ = distance faster runner goes in $\"+t+\"$ hrs
\n" ); document.write( "given:
\n" ); document.write( "Faster runner:
\n" ); document.write( " $\"+d+=+6t+\"$
\n" ); document.write( "Slower runner:
\n" ); document.write( " $\"+8+-+d+=+4t+\"$
\n" ); document.write( "-----------
\n" ); document.write( "By substitution:
\n" ); document.write( " $\"+8+-+6t+=+4t+\"$
\n" ); document.write( " $\"+10t+=+8+\"$
\n" ); document.write( " $\"+t+=+.8+\"$ hrs
\n" ); document.write( " $\"+.8%2A60+=+48+\"$
\n" ); document.write( " $\"+7+%2B+.8+\"$ hrs = 7:48 AM
\n" ); document.write( "-------------
\n" ); document.write( "check answer:
\n" ); document.write( " $\"+d+=+6t+\"$
\n" ); document.write( " $\"+d+=+6%2A.8+\"$
\n" ); document.write( " $\"+d+=+4.8+\"$ mi
\n" ); document.write( "and
\n" ); document.write( " $\"+8+-+d+=+4t+\"$
\n" ); document.write( " $\"+8+-+d+=+4%2A.8+\"$
\n" ); document.write( " $\"+8+-+d+=+3.2+\"$
\n" ); document.write( " $\"+d+=+8+-+3.2+\"$
\n" ); document.write( " $\"+d+=+4.8+\"$ mi
\n" ); document.write( "OK \n" ); document.write( "

\n" );