document.write( "Question 552480: tina invested 100 000 more than her husband did.if they both invested the money at 5 percent per year and their combined income from the investments was 35 000.how much did they invest in each? \n" ); document.write( "
Algebra.Com's Answer #360331 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Husband invested x \n" ); document.write( "wife x+100 000\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "interest = 5% = 0.05\r \n" ); document.write( "\n" ); document.write( "I = p*r*t\r \n" ); document.write( "\n" ); document.write( "35000= 0.05(x+100000) *1\r \n" ); document.write( "\n" ); document.write( "35000 = 0.05x +5000\r \n" ); document.write( "\n" ); document.write( "35000-5000= 0.05x \n" ); document.write( "30000=0.05x \n" ); document.write( "/0.05 \n" ); document.write( "x= 30000/0.05 \n" ); document.write( "x= 600,000 money invested by husband \n" ); document.write( "add 100000 for wife' investment \n" ); document.write( "m.ananth@hotmail.ca\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |