document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=552481>Question 552481</A>: <I><SPAN STYLE=\"word-break: break-all;\"> at 7:00am, two joggers start from opposite end of an 8 mile course. one jogger is running at a rate of 4mph, and the other is running at a rate og 6mph. at what time will the joggers meet? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #360329 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=360329\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> distance = 8 miles<BR>\n" );
document.write( "the runners are in opposite directions<BR>\n" );
document.write( "so add up speeds<BR>\n" );
document.write( "6+4 = 10 mph<BR>\n" );
document.write( "t=d/r<BR>\n" );
document.write( "8/10 = 4/5 of an hour<BR>\n" );
document.write( "4/5 *60 = 48 minutes\r<BR>\n" );
document.write( "\n" );
document.write( "They will meet at 7:48 AM </SPAN>\n" );
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