document.write( "Question 552489: Arnel invest some of his savings at 4 percent per year and an equal amount at 7 percent per year.His income totals ₱33 000 a year.How much did Rico invest at each rate? \n" ); document.write( "

Algebra.Com's Answer #360321 by JBarnum(2146) $\"\"$ $\"About$

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x = the amont invested in each interest rate
\n" ); document.write( "the amount(x) + the interest rate(.04x) added to the amount(x)+the interest rate (.07x)=total for the year(30000)
\n" ); document.write( " $\"1.04x%2B1.07x=30000\"$
\n" ); document.write( " $\"2.11x=30000\"$
\n" ); document.write( " $\"14218.01=x\"$ \r
\n" ); document.write( "\n" ); document.write( "check
\n" ); document.write( ".04x=568.72
\n" ); document.write( "568.72+14218.01
\n" ); document.write( "14786.73
\n" ); document.write( "and
\n" ); document.write( ".7x=995.26
\n" ); document.write( "995.26+14218.01
\n" ); document.write( "15213.27
\n" ); document.write( "so 14786.73+15213.27=30,000
\n" ); document.write( "correct \n" ); document.write( "

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