document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=552484>Question 552484</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the age of man is 10 years more than three times his brother's age. Find the age if 5 years from now he will be 4 years more than twice hi brothers age. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #360316 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=360316\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=brother's age now; x+5=age 5 years from now<BR>\n" );
document.write( "Then 3x+10=age of the man now;  3x+10+5=3x+15=age 5 years from now\r<BR>\n" );
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document.write( "And we are told that:<BR>\n" );
document.write( "3x+15=2(x+5)+4<BR>\n" );
document.write( "3x+15=2x+10+4<BR>\n" );
document.write( "3x+15=2x+14 subtract 15 and also 2x from each side<BR>\n" );
document.write( "3x-2x=-15+14<BR>\n" );
document.write( "x=-1   WHOAAAAAAAA!!!  CAN'T HAVE NEGATIVE AGES\r<BR>\n" );
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document.write( "THE FACT OF THE MATTER IS THAT IN 5 YEARS, THE MAN WILL BE 3(X+5) OR THREE TIMES AS OLD AS HIS BROTHER (X+5)\r<BR>\n" );
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document.write( "Hope this helps---ptaylor </SPAN>\n" );
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