document.write( "Question 552429: 2x+3y=9
\n" ); document.write( "3x+4y=5 \r
\n" ); document.write( "\n" ); document.write( "Solve using substitution \n" ); document.write( "

Algebra.Com's Answer #360276 by mananth(16946) $\"\"$ $\"About$

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2 x + 3 y = 9 .............1
\n" ); document.write( "3 x + 4 y = 5 .............2
\n" ); document.write( "Eliminate y
\n" ); document.write( "multiply (1)by -4
\n" ); document.write( "Multiply (2) by 3
\n" ); document.write( "-8 x -12 y = -36
\n" ); document.write( "9 x 12 y = 15
\n" ); document.write( "Add the two equations
\n" ); document.write( "1 x = -21
\n" ); document.write( "/ 1
\n" ); document.write( "x = -21
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "2 x + 3 y = 9
\n" ); document.write( "-42 + 3 y = 9
\n" ); document.write( " 3 y = 9 + 42
\n" ); document.write( " 3 y = 51
\n" ); document.write( " y = 17\r
\n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( "

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