document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=552397>Question 552397</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please solve<BR>\n" );
document.write( "4 1/3=(1/2)t </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #360272 by </B><A HREF=/tutors/aboutme.mpl?userid=TutorDelphia><B>TutorDelphia(193)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=TutorDelphia><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=TutorDelphia><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=360272\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Lets convert 4 1/3 to an improper fraction to start. Multiply 4*3 and add 1\r<BR>\n" );
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document.write( "13/3=(1/2)t<BR>\n" );
document.write( "We can either multiply by 2 or divide by 1/2 (and to divide by 1/2 we flip and multiply so we end up multiplying by 2/1 which is 2 anyway)<BR>\n" );
document.write( "26/3=t\r<BR>\n" );
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document.write( "Now just divide 26 by 3 and we ge 8 with a remainder of 2 so the answer is <BR>\n" );
document.write( "8 2/3=t </SPAN>\n" );
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