document.write( "Question 53777: Can someone help me on this problem?\r
\n" ); document.write( "\n" ); document.write( " The length of a rectangular playing field is 5 ft. less than twice its width. If the perimeter of the playing field is 230 ft., I nned to find the length and width of the field.\r
\n" ); document.write( "\n" ); document.write( " Thanks,
\n" ); document.write( " Sher
\n" ); document.write( "

Algebra.Com's Answer #36020 by jenrobrody(19)\"\" \"About 
You can put this solution on YOUR website!
let w=width
\n" ); document.write( "and since length is 5 less than twice the width,
\n" ); document.write( "length=2 times the width minus 5 or
\n" ); document.write( "length=2w-5
\n" ); document.write( "Perimeter=2*length+2*width:
\n" ); document.write( "Perimeter=2(2w-5)+2w=230
\n" ); document.write( "distribute:4w-10+2w=230
\n" ); document.write( "combine like terms:6w-10=230
\n" ); document.write( "add 10 to both sides: 6w=240
\n" ); document.write( "divide by 6: w=40
\n" ); document.write( "so length= 2(40) - 5 = 80 - 5 = 75 \r
\n" ); document.write( "\n" ); document.write( "check: 2*(40) + 2*(75) = 80 +150 =230
\n" ); document.write( "
\n" );