document.write( "Question 53777: Can someone help me on this problem?\r
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document.write( " The length of a rectangular playing field is 5 ft. less than twice its width. If the perimeter of the playing field is 230 ft., I nned to find the length and width of the field.\r
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document.write( " Thanks,
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document.write( " Sher \n" );
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Algebra.Com's Answer #36018 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The length of a rectangular playing field is 5 ft. less than twice its width. If the perimeter of the playing field is 230 ft., I nned to find the length and width of the field. \n" ); document.write( "-------------- \n" ); document.write( "Let the width be \"x\" ft. \n" ); document.write( "Then the length is \"2x-5\" \n" ); document.write( "Perimeter = 2(length+width) \n" ); document.write( "230 = 2(2x-5+x) \n" ); document.write( "230=2(3x-10) \n" ); document.write( "115=3x-10 \n" ); document.write( "3x=125 \n" ); document.write( "x=41 2/3 ft (This is the width) \n" ); document.write( "2x-5= 78 1/3 ft (This is the length) \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |