document.write( "Question 53777: Can someone help me on this problem?\r
\n" ); document.write( "\n" ); document.write( " The length of a rectangular playing field is 5 ft. less than twice its width. If the perimeter of the playing field is 230 ft., I nned to find the length and width of the field.\r
\n" ); document.write( "\n" ); document.write( " Thanks,
\n" ); document.write( " Sher
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Algebra.Com's Answer #36018 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
The length of a rectangular playing field is 5 ft. less than twice its width. If the perimeter of the playing field is 230 ft., I nned to find the length and width of the field.
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\n" ); document.write( "Let the width be \"x\" ft.
\n" ); document.write( "Then the length is \"2x-5\"
\n" ); document.write( "Perimeter = 2(length+width)
\n" ); document.write( "230 = 2(2x-5+x)
\n" ); document.write( "230=2(3x-10)
\n" ); document.write( "115=3x-10
\n" ); document.write( "3x=125
\n" ); document.write( "x=41 2/3 ft (This is the width)
\n" ); document.write( "2x-5= 78 1/3 ft (This is the length)
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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