document.write( "Question 551945: The sum of the present ages of Joey and his mother is 46 years. In 4 years, Joey will be 3 years older than one-half as old as his mother at that time. Find the present ages of Joey and his mother. \n" ); document.write( "
Algebra.Com's Answer #360116 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! he sum of the present ages of Joey and his mother is 46 years. \n" ); document.write( " In 4 years, Joey will be 3 years older than one-half as old as his mother at that time. \n" ); document.write( " Find the present ages of Joey and his mother. \n" ); document.write( ": \n" ); document.write( "Let m = mom's present age \n" ); document.write( "Let j = Joey's \n" ); document.write( ": \n" ); document.write( "write an equation for each statement: \n" ); document.write( ": \n" ); document.write( "\"The sum of the present ages of Joey and his mother is 46 years.\" \n" ); document.write( "m + j = 46 \n" ); document.write( "j = (46-m); we can use this form for substitution \n" ); document.write( ": \n" ); document.write( "\" In 4 years, Joey will be 3 years older than one-half as old as his mother at that time.\" \n" ); document.write( "j + 4 = .5(m + 4) + 3 \n" ); document.write( "j + 4 = .5m + 2 + 3 \n" ); document.write( "j = .5m + 5 - 4 \n" ); document.write( "j = .5m + 1 \n" ); document.write( "Replace j with (46-m) \n" ); document.write( "46-m = .5m + 1 \n" ); document.write( "46 - 1 = .5m + m \n" ); document.write( "45 = 1.5m \n" ); document.write( "m = \n" ); document.write( "m = 30 yrs is mom's age \n" ); document.write( "then \n" ); document.write( "j = 46 - 30 \n" ); document.write( "j = 16 yrs is Joey's age \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this in the statement: \n" ); document.write( "\"In 4 years, Joey will be 3 years older than one-half as old as his mother at that time. \" \n" ); document.write( "16 + 4 = .5(30+4) + 3 \n" ); document.write( "20 = .5(34) + 3 \n" ); document.write( "20 = 17 + 3 \n" ); document.write( " |