document.write( "Question 6629: How do I solve the equation, \"+log%289%2C+%28b%2B4%29%29+-+log%289%2C+%28b-3%29%29+=+log%289%2C+8%29+\" \n" ); document.write( "
Algebra.Com's Answer #3601 by prince_abubu(198)\"\" \"About 
You can put this solution on YOUR website!
First up, use the property \"+log%28b%2Ca%29+-+log%28b%2Cc%29+=+log%28b%2C%28a%2Fc%29%29+\".\r
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\n" ); document.write( "\n" ); document.write( "So using that, \"+log%289%2C%28%28b%2B4%29%2F%28b-3%29%29%29+=+log%289%2C8%29+\"\r
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\n" ); document.write( "\n" ); document.write( "Since both sides of the equation are log base 9, we can simply say \r
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\n" ); document.write( "\n" ); document.write( "\"+%28b%2B4%29%2F%28b-3%29+=+8+\"\r
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\n" ); document.write( "\n" ); document.write( "\"+b+%2B+4+=+8%28b+-+3%29+\" <---- multiply both sides by (b-3)\r
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\n" ); document.write( "\n" ); document.write( "\"+b+%2B+4+=+8b+-+24+\" <---- Solve for b\r
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\n" ); document.write( "\n" ); document.write( "\"+28+=+7b+\" <----- combine like terms across equals sign\r
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\n" ); document.write( "\n" ); document.write( "\"+b+=+4+\" <---- finally solve for b
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