document.write( "Question 551996: Solve each of these systems using the substitution method.
\n" ); document.write( "2x + 3y = -4\r
\n" ); document.write( "\n" ); document.write( "x - 2y = 5\r
\n" ); document.write( "\n" ); document.write( "Any help will be Greatly Appreciated!
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Algebra.Com's Answer #360070 by 10301650(32)\"\" \"About 
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GIVEN:
\n" ); document.write( " 2x+3y=-4
\n" ); document.write( " x-2y=5\r
\n" ); document.write( "\n" ); document.write( " --(use the second given to look for the X)
\n" ); document.write( " x-2y=5
\n" ); document.write( "(transfer the -2y to the other side)
\n" ); document.write( " x=2y+5 (use this one to solve or the X)\r
\n" ); document.write( "\n" ); document.write( " --(now use the first given to substitute the second given)
\n" ); document.write( " 2x+3y=-4
\n" ); document.write( " 2(2y+5)+3y=-4
\n" ); document.write( " 4y+10+3y=-4
\n" ); document.write( " 7y+10=-4
\n" ); document.write( " 7y=-10-4
\n" ); document.write( " 7y=-14
\n" ); document.write( " (divide both sides with 7)
\n" ); document.write( " y=-2 (answer for Y)\r
\n" ); document.write( "\n" ); document.write( " --(NOW, use the second given to solve for X)
\n" ); document.write( " x-2y=5
\n" ); document.write( " x-2(-2)=5
\n" ); document.write( " x+4=5
\n" ); document.write( " x=-4+5
\n" ); document.write( " x=1(answer for X)
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