document.write( "Question 53726: A train leaves Roseville heading east at 6:00 am at 40 miles per hour. another eastbound train leaves on a parallel track at 7 am at 50 miles per hour. What time will it be when the two trains are the same distance away from Roseville? \n" ); document.write( "
Algebra.Com's Answer #36007 by ankor@dixie-net.com(22740)\"\" \"About 
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A train leaves Roseville heading east at 6:00 am at 40 miles per hour. another eastbound train leaves on a parallel track at 7 am at 50 miles per hour. What time will it be when the two trains are the same distance away from Roseville?
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\n" ); document.write( "Let t = time in hrs required by the 1st train which leaves at 6:00 am
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\n" ); document.write( "The 2nd train leaves an hour later so it's time will be (t-1)
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\n" ); document.write( "Dist = speed * time:
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\n" ); document.write( "1st train dist = 2nd train dist
\n" ); document.write( " 40t = 50(t-1)
\n" ); document.write( " 40t = 50t - 50
\n" ); document.write( " 40t - 50t = -50
\n" ); document.write( " -10t = -50
\n" ); document.write( " t = -50/-10
\n" ); document.write( " t = +5 hours
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\n" ); document.write( "Add 5 hrs to 6:00 am; at 11:00 am they will be the same distance:
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\n" ); document.write( "2nd train travels only 4 hours,
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\n" ); document.write( "check our solutions using distance: 40*5 = 50*4
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