document.write( "Question 53742: I don't understand how you do this problem. The perimeter of a rectangle is 24 inches. Find the dimensions if its length is 3 inches greater than its width.
\n" ); document.write( "Will you please just put this problem in numbers and letters not words? Thanx
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Algebra.Com's Answer #36003 by aaaaaaaa(138)\"\" \"About 
You can put this solution on YOUR website!
Since your biggest problem seems to be converting the problem into an equation, I'll give that a bit more emphasis:\r
\n" ); document.write( "\n" ); document.write( "The perimeter of a rectangle is 24 inches. Find the dimensions if its length is 3 inches greater than its width.\r
\n" ); document.write( "\n" ); document.write( "Let's define what variables we'll need and what they stand for:\r
\n" ); document.write( "\n" ); document.write( "width = x (I named it x because I wanted to; length would work just as fine)
\n" ); document.write( "length = x+3 (The length is 3 inches greater than the width)\r
\n" ); document.write( "\n" ); document.write( "The perimeter of a rectangle is the sum of the length of all of its sides (width+width+height+height), therefore the perimeter of our rectangle is \"x%2Bx%2Bx%2B3%2Bx%2B3\". Since we know that equals 24, we have an equation!\r
\n" ); document.write( "\n" ); document.write( "\"x%2Bx%2Bx%2B3%2Bx%2B3+=+24\"
\n" ); document.write( "\"4x+%2B+6+=+24\"
\n" ); document.write( "\"4x+=+18\"
\n" ); document.write( "\"x+=+18%2F4\" or 4 1/2 inches. The length, therefore, is that number plus 3, or 7 1/2 inches.\r
\n" ); document.write( "\n" ); document.write( "Checking:\r
\n" ); document.write( "\n" ); document.write( "7 1/2 * 2 + 4 1/2 * 2 =
\n" ); document.write( "15 + 9 =
\n" ); document.write( "24
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