document.write( "Question 53763: The problem is...The length of a rectangular playing field is 5 ft less than twice its width.
\n" ); document.write( "If the perimeter of the playing field is 230 ft, find the length and width of the field.\r
\n" ); document.write( "\n" ); document.write( "I thought you would go length times width, but for some reason the added numbers are confusing me. wouldnt 5x-2x=230? \n" ); document.write( "

Algebra.Com's Answer #35999 by aaaaaaaa(138) $\"\"$ $\"About$

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Length times width is the area, we want the perimeter, which is the sum of all the lengths of the sides (width+width+length+length).\r
\n" ); document.write( "\n" ); document.write( "Let's call width x. If the length is 5 less than twice x, it'll be 2x-5. Now we equal the perimeter to 230 and solve:\r
\n" ); document.write( "\n" ); document.write( " $\"x+%2B+x+%2B+2x-5+%2B+2x-5+=+230\"$
\n" ); document.write( " $\"4x+-+10+=+230\"$
\n" ); document.write( " $\"4x+=+240\"$
\n" ); document.write( " $\"x+=+60\"$ \r
\n" ); document.write( "\n" ); document.write( "If the width is 60 ft, the length will be 2*60 - 5 = 115 ft. \n" ); document.write( "

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