document.write( "Question 53764: Got an algebra question. Suppose 8 is less than X, and X is less than 12. Write an \"absolute value\" inequality that is equivalent to this compound inequality.\r
\n" ); document.write( "\n" ); document.write( "I can turn an absolute value inequality to a compound inequality, but can't seem to turn this compound into an absolute value inequality.\r
\n" ); document.write( "\n" ); document.write( "Thanks for the assist.
\n" ); document.write( "Respectfully,
\n" ); document.write( "Joe Hoerth
\n" ); document.write( "Coppell, Texas
\n" ); document.write( "

Algebra.Com's Answer #35998 by aaaaaaaa(138)\"\" \"About 
You can put this solution on YOUR website!
8 is less than X, and X is less than 12:\r
\n" ); document.write( "\n" ); document.write( "\"8+%3C+x+%3C+12\"\r
\n" ); document.write( "\n" ); document.write( "The difference between 8 and 12 is 4. Half of 4 is 2. Therefore, since we want an absolute value inequality, we need to change those values (8 and 12) into numbers with opposite signs. The ones that will work are -2 and 2. Now that we know that, it's pretty easy:\r
\n" ); document.write( "\n" ); document.write( "\"8+%3C+x+%3C+12\"
\n" ); document.write( "\"8+-+10+%3C+x+-+10+%3C+12+-+10\"
\n" ); document.write( "\"-2+%3C+x+-+10+%3C+2\"\r
\n" ); document.write( "\n" ); document.write( "\"abs%28x-10%29+%3C+2\"
\n" ); document.write( "
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