document.write( "Question 551749: A number is doubled and then the product is increased by 6. This sum is then multiplied by -3, and the result is 54 greater than three times the opposite of the number. What is the number? \n" ); document.write( "
Algebra.Com's Answer #359949 by ankor@dixie-net.com(22740)\"\" \"About 
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A number is doubled and then the product is increased by 6.
\n" ); document.write( " This sum is then multiplied by -3, and the result is 54 greater than three times the opposite of the number.
\n" ); document.write( " What is the number?
\n" ); document.write( ":
\n" ); document.write( "Let x = the number
\n" ); document.write( "then
\n" ); document.write( "-x = the opposite of the number
\n" ); document.write( ":
\n" ); document.write( "-3(2x+6) = 3(-x) + 54
\n" ); document.write( "-6x - 18 = -3x + 54
\n" ); document.write( "-18 - 54 = -3x + 6x
\n" ); document.write( "-72 = 3x
\n" ); document.write( "x = \"%28-72%29%2F3\"
\n" ); document.write( "x = -24 is the number
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Confirm this in the original statement:
\n" ); document.write( "-3(2(-24) + 6 = 3(24) + 54
\n" ); document.write( "-3(-48 + 6) = 72 + 54
\n" ); document.write( "-3(-42) = 126
\n" ); document.write( "126 = 126; confirms our solution of x=-24 \n" ); document.write( "
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