document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=551693>Question 551693</A>: <I><SPAN STYLE=\"word-break: break-all;\"> when will\r<BR>\n" );
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document.write( "lim  [(ax^2 + bx + c)/ (x^2 - x -6)] = 1<BR>\n" );
document.write( "x->0   \r<BR>\n" );
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document.write( "a) a = 0<BR>\n" );
document.write( "b) a = 1<BR>\n" );
document.write( "c) b = -1<BR>\n" );
document.write( "d) c = -6 \r<BR>\n" );
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document.write( "im getting 2 different answers so Im a bit confused...<BR>\n" );
document.write( "Please can some one explain it to me with solution thanks... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #359883 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=359883\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We can substitute directly because the function is continuous everywhere near 0 (the only \"problems\" are near -2 and 3), and obtain c = -6. We cannot claim any of the other choices, because they may or may not be true. Additionally, we cannot use L'Hopital's rule, because we need both limits to equal 0 or infinity. </SPAN>\n" );
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