document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=551630>Question 551630</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangular lot is to be bounded by a fence on three sides and by a wall on the fourth side. Two kinds of fencing will be used with heavy duty fencing selling for $4 a foot on the side opposite the wall. The two remaining sides will use standard fencing selling for $3 a foot. What are the dimensions of the rectangular plot of greatest area that can be fenced in at a cost of $6600? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #359881 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=359881\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A rectangular lot is to be bounded by a fence on three sides and by a wall on the fourth side.<BR>\n" );
document.write( " Two kinds of fencing will be used with heavy duty fencing selling for $4 a foot on the side opposite the wall. <BR>\n" );
document.write( "The two remaining sides will use standard fencing selling for $3 a foot. <BR>\n" );
document.write( "What are the dimensions of the rectangular plot of greatest area that can be fenced in at a cost of $6600?<BR>\n" );
document.write( ":<BR>\n" );
document.write( "The perimeter<BR>\n" );
document.write( " P = L + 2W<BR>\n" );
document.write( "The cost<BR>\n" );
document.write( "4L + 3(2W) = $6600<BR>\n" );
document.write( "4L + 6W = $6600<BR>\n" );
document.write( "4L = (6600-6W)<BR>\n" );
document.write( "divide both sides by 4<BR>\n" );
document.write( "L = 1650 - 1.5W<BR>\n" );
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document.write( "The area:<BR>\n" );
document.write( "A = L * W<BR>\n" );
document.write( "Replace L with (1650-1.5w)<BR>\n" );
document.write( "A = W(1650-1.5W)<BR>\n" );
document.write( "A quadratic equation<BR>\n" );
document.write( "A = -1.5w^2 + 1650w<BR>\n" );
document.write( "Find the axis of symmetry: x = -b/(2a); In this equation: a=-1.5; b=1650<BR>\n" );
document.write( "w = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-1650%29%2F%282%2A-1.5%29 ALIGN=MIDDLE  ALT=\"%28-1650%29%2F%282%2A-1.5%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "w = +550 ft is the width<BR>\n" );
document.write( "find the length<BR>\n" );
document.write( "L = 1650 - 1.5(550)<BR>\n" );
document.write( "L = 825 ft is the length<BR>\n" );
document.write( ":<BR>\n" );
document.write( "An area 825 by 550 ft gives max area for $6600<BR>\n" );
document.write( ":<BR>\n" );
document.write( ":<BR>\n" );
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document.write( "See if this checks out<BR>\n" );
document.write( "4(825) + 3(2(550)) = <BR>\n" );
document.write( "3300 + 3300 = $6600 </SPAN>\n" );
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