document.write( "Question 551707: How much pure acid must be added to 50ml of 25% acid solution to produce a mixture that is 60% acid \n" ); document.write( "
Algebra.Com's Answer #359852 by mananth(16946)\"\" \"About 
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percent ---------------- quantity
\n" ); document.write( "Acid 25 ----------------50 ml
\n" ); document.write( "Pure acid 100 ----------------x ml
\n" ); document.write( "Mixture 60 ---------------- 50+xml
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\n" ); document.write( "25*50+100x=60(50+x)
\n" ); document.write( "1250+100x=3000+60x
\n" ); document.write( "100x-60 x=3000 -1250
\n" ); document.write( "40 x = 1750
\n" ); document.write( "/ 40
\n" ); document.write( "x= 43.75 ml of Pure acid
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