document.write( "Question 551707: How much pure acid must be added to 50ml of 25% acid solution to produce a mixture that is 60% acid \n" ); document.write( "
Algebra.Com's Answer #359852 by mananth(16946)![]() ![]() You can put this solution on YOUR website! percent ---------------- quantity \n" ); document.write( "Acid 25 ----------------50 ml \n" ); document.write( "Pure acid 100 ----------------x ml \n" ); document.write( "Mixture 60 ---------------- 50+xml \n" ); document.write( " \n" ); document.write( "25*50+100x=60(50+x) \n" ); document.write( "1250+100x=3000+60x \n" ); document.write( "100x-60 x=3000 -1250 \n" ); document.write( "40 x = 1750 \n" ); document.write( "/ 40 \n" ); document.write( "x= 43.75 ml of Pure acid \n" ); document.write( " \n" ); document.write( " |