document.write( "Question 53676: 4&2/3 / 12 \n" ); document.write( "
Algebra.Com's Answer #35985 by rchill(405)\"\" \"About 
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You have a complex fraction here, so change the 4&2/3 to \"14%2F3\" and the equation is now \"%2814%2F3%29%2F12\". That means to solve, you multiply the reciprical of the denominator 12 with the numerator. So, we now have \"%2814%2F3%29%2A%281%2F12%29\". That simplifies to \"14%2F36\", which reduces to \"7%2F18\". \n" ); document.write( "
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