document.write( "Question 551668: At 6 AM, Joe set out on a hike from his home and walked at an average speed of 5 kilometers per hour. after walking a certain distance, he noticed that he forgot his lunch box. He rode a jeep and went back home at a speed of 45 kilometers per hour. If he reached his home at 7 AM how far has he walked? \n" ); document.write( "
Algebra.Com's Answer #359841 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let the distance he walked be x \n" ); document.write( "t=d/r \n" ); document.write( "time taken to walk = x/5 \n" ); document.write( "he went by jeep. \n" ); document.write( "time taken by jeep = x/45\r \n" ); document.write( "\n" ); document.write( "time to reach home = 1 hour\r \n" ); document.write( "\n" ); document.write( "walking time + jeep time = 1\r \n" ); document.write( "\n" ); document.write( "x/5+x/45 =1\r \n" ); document.write( "\n" ); document.write( "LCD = 45 \n" ); document.write( "multiply the equation by 45 \n" ); document.write( "9x+x=45 \n" ); document.write( "10x=45 \n" ); document.write( "/10 \n" ); document.write( "x=4.5 km\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |