document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=551574>Question 551574</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The second angle of a triangle is 3 times as large as the first. The third angle is 12 degrees more than the sum of the other two angles. Find the measure of each angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #359827 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=359827\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> angle I x <BR>\n" );
document.write( "Angle II 3x<BR>\n" );
document.write( "Angle III = x+3x+12= 4x+12\r<BR>\n" );
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document.write( "x+3x+4x+12=180 ( sum of angles of triangle = 180 deg.)\r<BR>\n" );
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document.write( "8x+12=180<BR>\n" );
document.write( "8x=180-12<BR>\n" );
document.write( "8x=168<BR>\n" );
document.write( "/8<BR>\n" );
document.write( "x=21<BR>\n" );
document.write( "angle I = 21<BR>\n" );
document.write( "Angle II = 63<BR>\n" );
document.write( "Angle III = 96 </SPAN>\n" );
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