document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=551635>Question 551635</A>: <I><SPAN STYLE=\"word-break: break-all;\">  housewife wishes to mix coffee beans worth Php60 and Php85 a kilogram to obtain 50 kilograms of coffee beans worth Php70 a kilogram. How many kilograms of each should she use? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #359810 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=359810\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> housewife wishes to mix coffee beans worth Php60 and Php85 a kilogram to obtain 50 kilograms of coffee beans worth Php70 a kilogram. How many kilograms of each should she use?<BR>\n" );
document.write( "Let x = amount (kilograms) of Php60 coffee beans<BR>\n" );
document.write( "then<BR>\n" );
document.write( "50-x = amount (kilograms) of Php85 coffee beans<BR>\n" );
document.write( ".<BR>\n" );
document.write( "60x + 85(50-x) = 70(50)<BR>\n" );
document.write( "60x + 4250-85x = 3500<BR>\n" );
document.write( "4250-25x = 3500<BR>\n" );
document.write( "-25x = 3500-4250<BR>\n" );
document.write( "-25x = -750<BR>\n" );
document.write( "x = 30 kilograms of Php60 coffee beans<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Php85 coffee beans:<BR>\n" );
document.write( "50-x = 50-30 = 20 kilograms\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
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