document.write( "Question 551594: A rectangle has a perimeter of 34 cm and an area of 52 cm. Its length is 5 more than twice its width. Write and solve a system of equations to find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #359793 by oberobic(2304)\"\" \"About 
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2(L+W) = 34
\n" ); document.write( "L + W = 17
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\n" ); document.write( "L*W = 52
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\n" ); document.write( "L = 2W+5
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\n" ); document.write( "2L + 2W = 34
\n" ); document.write( "L - 2W = 5
\n" ); document.write( "--------------- add
\n" ); document.write( "3L = 39
\n" ); document.write( "L = 13
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\n" ); document.write( "L+W = 17
\n" ); document.write( "W = 4
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\n" ); document.write( "Check perimeter.
\n" ); document.write( "2*(13+4) = 34
\n" ); document.write( "Check area.
\n" ); document.write( "13*4 = 42
\n" ); document.write( "Check relationship between L and W.
\n" ); document.write( "L = 2*W + 5 ??
\n" ); document.write( "Yes.
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\n" ); document.write( "Answer: Length = 13; Width 4
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\n" ); document.write( "Done.
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