document.write( "Question 551594: A rectangle has a perimeter of 34 cm and an area of 52 cm. Its length is 5 more than twice its width. Write and solve a system of equations to find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #359793 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! 2(L+W) = 34 \n" ); document.write( "L + W = 17 \n" ); document.write( ". \n" ); document.write( "L*W = 52 \n" ); document.write( ". \n" ); document.write( "L = 2W+5 \n" ); document.write( ". \n" ); document.write( "2L + 2W = 34 \n" ); document.write( "L - 2W = 5 \n" ); document.write( "--------------- add \n" ); document.write( "3L = 39 \n" ); document.write( "L = 13 \n" ); document.write( ". \n" ); document.write( "L+W = 17 \n" ); document.write( "W = 4 \n" ); document.write( ". \n" ); document.write( "Check perimeter. \n" ); document.write( "2*(13+4) = 34 \n" ); document.write( "Check area. \n" ); document.write( "13*4 = 42 \n" ); document.write( "Check relationship between L and W. \n" ); document.write( "L = 2*W + 5 ?? \n" ); document.write( "Yes. \n" ); document.write( ". \n" ); document.write( "Answer: Length = 13; Width 4 \n" ); document.write( ". \n" ); document.write( "Done. \n" ); document.write( " |