document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=551547>Question 551547</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One of two supplementary angles is 30 degrees greater than twice the other. Find the degree measure of each angle.<BR>\n" );
document.write( " That's the question. Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #359776 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=359776\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> one angle be x<BR>\n" );
document.write( "supplement  will be 180-x\r<BR>\n" );
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document.write( "x= 2(180-x)+30<BR>\n" );
document.write( "x=360-2x+30<BR>\n" );
document.write( "x+2x=360+30<BR>\n" );
document.write( "3x=390<BR>\n" );
document.write( "/3<BR>\n" );
document.write( "x=130 deg<BR>\n" );
document.write( "supplement = 180-130=50 deg<BR>\n" );
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