document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=551505>Question 551505</A>: <I><SPAN STYLE=\"word-break: break-all;\">  James is four years younger than Austin. If three times James' age is increased by the square of Austin's age, the result is 28. Find the ages of James and Austin. (Algebraic solutions only) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #359765 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=359765\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \"James is four years younger than Austin\" ___ j = a - 4\r<BR>\n" );
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document.write( "\"If three times James' age is increased by the square of Austin's age, the result is 28\"<BR>\n" );
document.write( "___ 3j + a^2 = 28\r<BR>\n" );
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document.write( "substituting ___ 3(a - 4) + a^2 = 28 ___ a^2 + 3a - 40 = 0 ___ (a + 8)(a - 5) = 0\r<BR>\n" );
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document.write( "solve for a, then substitute back to find j </SPAN>\n" );
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